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8k^2+24k-32=0
a = 8; b = 24; c = -32;
Δ = b2-4ac
Δ = 242-4·8·(-32)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-40}{2*8}=\frac{-64}{16} =-4 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+40}{2*8}=\frac{16}{16} =1 $
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